Login
Remember
Register
Questions and Answers
Questions
Hot!
Unanswered
Tags
Users
Ask a Question
Badges
Ask a Question
y=-f(x+5)+4
0
votes
asked
Dec 19, 2012
by
anonymous
Sketch the parabola y=-f(x+5)+4 where the original parent function isf(x)=x^2 . Label the vertex, roots, y-intercept, and axis of symmetry.
precalculus problems
help
please
urgent
Your comment on this question:
Your name to display (optional):
Email me at this address if a comment is added after mine:
Email me if a comment is added after mine
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please
log in
or
register
.
Your answer
Your name to display (optional):
Email me at this address if my answer is selected or commented on:
Email me if my answer is selected or commented on
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please
log in
or
register
.
1 Answer
0
votes
answered
Dec 20, 2012
by
anonymous
f=x^2
y=-f(x+5)+4
y=-(x+5)^2+4
parabola that kerv down
y=-x^2 -10x -21...set =0 & get (x+3)(x+7)=0
so y=0 at x=-3 & x=-7
dy/dx =-2x-10, set =0 tu get horizontal tangent...at x=-5
the top av parabola
Your comment on this answer:
Your name to display (optional):
Email me at this address if a comment is added after mine:
Email me if a comment is added after mine
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please
log in
or
register
.
Welcome to Questions and Answers, where you can ask questions and receive answers from other members of the community.
...